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Aptitude - Clock - Discussion

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"Nothing is impossible to a willing heart."
- (Proverb)
6. 

At what time between 7 and 8 o'clock will the hands of a clock be in the same straight line but, not together?

[A]. 5 min. past 7[B].
5 2 min. past 7
11
[C].
5 3 min. past 7
11
[D].
5 5 min. past 7
11

Answer: Option C

Explanation:

When the hands of the clock are in the same straight line but not together, they are 30 minute spaces apart.

At 7 o'clock, they are 25 min. spaces apart.

Minute hand will have to gain only 5 min. spaces.

55 min. spaces are gained in 60 min.

5 min. spaces are gained in 60 x 5 min = 5 5 min.
55 11

Required time = 5 5 min. past 7.
11


Nithya said: (Thu, Jun 3, 2010 01:10:25 AM)    
 
How is that at 7 o'clock they are 25 min space apart ?

Nitesh Nandwana said: (Wed, Oct 13, 2010 09:25:11 AM)    
 
@Nithya.

This is very simple just see clock at the time of 7 o'clock.

The difference between hour hand and minute is 25 min.

Gopal said: (Wed, Oct 27, 2010 04:27:40 AM)    
 
I think they are counting clock wise direction from hour hand to minute hand. If they count from minute hand to hour hand it will be 35 mins

Aparna said: (Sun, Jan 2, 2011 09:08:43 AM)    
 
Simple method:

In one hour,once minute hand and hour hand comes in straight line
so our answer is something 7 past,not 8 past
use formula,
titha(0)=30h-11/2m
titha is 180,hour hand is on 7
put values
we get titha=60/11
convert into quotitent*remainder/divisor format
we get
5*5/11

So answer is 5*5/11 past 7.

Karthik said: (Wed, Feb 23, 2011 12:11:24 AM)    
 
In 1 hour the min hand will gain 60 min and the hour hand will gain 5 min (i.e if the time is 5 the hour hand will take 5 min spaces to reach 6) so 60-5= 55

Did you understand this?

Fatima said: (Wed, Jun 8, 2011 07:49:45 AM)    
 
Please someone clear that what angle in 8o'clock9 between.

Harshad said: (Mon, Jun 13, 2011 06:20:07 AM)    
 
How do you know that at 7 the difference is 25min?

@ Nitesh: Assuming I don't have a watch to look at and count the minutes.

Vivek Jain said: (Fri, Jul 1, 2011 08:22:58 AM)    
 
How 55 min. spaces are gained in 60 min. ?

Please somebody tell me!

Scientist said: (Sat, Jul 9, 2011 05:31:37 AM)    
 
Dear aparna how did you got 11/2 ?

Faiz said: (Sun, Aug 7, 2011 11:09:34 PM)    
 
@Harshad

Man at 7 o clock, the hour hand is at 7 and the minute hand is in 12 i.e 60th min. assume the display in your watch is like 5 10 15.. 60.. so at 7 the hour hand will be at 35 and the min hand will be in 60.. now jus go on adding the minute space clockwise or els simple (60-35) gives 25 mins space..!!

Pritam said: (Fri, Aug 19, 2011 10:17:40 AM)    
 
How 55 min. spaces are gained in 60 min?

Can anybody explain?

Rakesh said: (Sat, Aug 27, 2011 06:22:44 AM)    
 
Can some one give me a simple way to solve these watch question ?

Puja Ahirwal said: (Sat, Sep 17, 2011 09:58:00 PM)    
 
Please tell me about when minute space are add or subtract.

Marati Raju said: (Tue, Sep 27, 2011 04:31:44 PM)    
 
This problem is very simple . . . .
For this problem
in clock 7 ki opposite 1 i.e 5min
hence at 5:[5/11]min past 7 O'clock at that time hands of a clock be in straight line
or
at 60/11 min past 7
the hands of a clock on straight line . . . . .

Rajendra Sahu said: (Mon, Jan 16, 2012 08:01:48 PM)    
 
For straight line angle =180
The formula is for finding angle =30H-(11/2)*M
where H =>Hours
M => Minute.
Now

30H-(11/2)*M=180
30*7-(11/2)*M=180
210 - (11/2)*M=180
-(11/2)*M=180-210
-(11/2)*M=-30
11*M=60 (Cross Multiply)
M=60/11 minutes
means 5+5/11 minute

So Time will be

(5+5/11) minute and 7 past

Amit said: (Wed, Jan 18, 2012 04:27:50 PM)    
 
What is the formula? whether its 11/2*min-30hr or 30hr-11/2*min?

Shekhar said: (Thu, Feb 2, 2012 06:21:30 PM)    
 
@amit:11/2min-30h this formula applicable only when h<6
if u put h=6 or above then the min>60 which is not acceptable(for the 180 degree),
in this problem if we put that formula then the ans is 77(10/11)
but in that case the h=7 so we apply the another formula which is 30h-11/2
in this case if we put that then formula the ans is 5(5/11)
if u apply that formula then u will find that min<60 which is acceptable

BASICALLY WE NEED THIS 2 FORMULAS BUT IN DIFF CASE...
hope u will understand:)

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