K.Kiran Kumar said:
(Wed, Aug 4, 2010 12:48:55 AM)
I cant get the question what it means. Please someone try to explain it.
Ravi said:
(Tue, Aug 24, 2010 12:52:05 PM)
I can't understand this: (60/55*60) why this step is used. Please someone explain me?
Tarak B Patel said:
(Wed, Aug 25, 2010 03:21:35 PM)
Solution:
In 1 hour both the hands cover 55 min space.
=> 60/55 = 12/11 min space covered in 1min of the actual time.
for the hand to coincide hands have to cover 60 min space
=> 12/11 * 60 = 720/11 = 65.5/11 min in actual clock.
But the clock coincides every 64 min.
=>65.5/11 - 64 = 1.5/11 = 16/11 min loss in 64min.
=>16/11 * 1/64 = 1/44 min loss in 1min.
Loss In 24 Hrs => 1/44 * (24 *60) = 360/11 = 32.8/11 min the clock looses in a day.
Soumya said:
(Wed, Jan 12, 2011 01:18:58 AM)
Why we multiply 1/64 ?
Priya said:
(Fri, Jun 24, 2011 12:12:21 PM)
How 55 spaces in 60 mins? couldnt get that.
Sharat said:
(Wed, Dec 14, 2011 11:01:53 AM)
What is this min. space?
Does it mean the min. hand lags the hour by 5 min. space ?
Maddy said:
(Fri, Jan 13, 2012 05:58:35 PM)
To coincide with each other space(ticks) between them should be ZERO(no space).
Consider starting from 12 noon.
in 1 hr--> min hand covers spaces(ticks) =60
in 1 hr--> hour hand covers spaces(ticks) = 5
so in 1 min --> hour hand covers 5/60=1/12 space(tick)
so after 1 hr=60 mins (1.00) spaces between them will be equal to 5
so have to cover 5 places for minute hand to meet hour hand
total time = 60+5 ... but in 5 mins hour hand will further go ahead by 5*1/12 ticks
so have to cover 5/12 ticks for minute hand to meet
total time = 60+5+5/12 ... but agin in 5/12 mins hour hand will go ahead buy 5/12*1/12= 5/12^2... and so on
So total time will be = 60+5+(5/12+5/12^2+5/12^3+.........) this GP
total time to meet = 720/11 i.e., 65.(5/11).
This time required to coincide hands in correct clock... solve accordingly.
Karthik said:
(Wed, Mar 21, 2012 03:55:52 PM)
How can the watch lose time if it is covering earlier than what is expected?
Himanshu Dewangan said:
(Mon, Mar 26, 2012 11:18:05 AM)
It is universal truth that watch does not lose any time.Every day start from 12:00 am in night, hr. and min hand positioned at 0 degree,than how lose? no lose is there..
But suppose hands coincide every 64 min.
(In really it is not possible..eg if ones they coincide it take 65+5/11 min always for next)
there will be lose of 65+5/11 - 64= 16/11 from actual or real time in 65+5/11 min.
So calculate lose in 1 day= 24*60 min
Vallaban said:
(Wed, Apr 4, 2012 11:22:18 AM)
55 min. Spaces are gained by minute hand in 60 min period.
To find how many spaces it has actually gained, we need to fix a standard point first. !
With respect to it, we need to see the difference by how much is it actually varying. !
So let us assume the standard point to be the place where the minutes hand and hours hand has been coincided. !
I may be 12:00, 1.06, 2.11, 3.17. etc. from there. 60 minutes implies the minute hand must come back to the same point where it has started. !
Is it not. ?
Now, 60 minute passed and so minute hand covers 60 minute spaces.
And the hour hand advances by 5 minute spaces. !
So from the standard point fixed initially (we assumed the standard point is where the minute point and hours hand were coinciding. Also. 60 minutes will be passed when the minute hand comes back to the same position from where it started).
Now, there is.
An absolute 60 min spaces covered by minute hand in 60 min and then there is 5 min spaces advanced by hour hand in 60 min period. !
So on total.
Total advancement is 60-5 = 55 minute spaces. !
Prasant said:
(Fri, Apr 13, 2012 01:14:54 AM)
Pleaes clarify, whether the clock looses or gain in this question?
Naresh said:
(Wed, May 30, 2012 04:45:01 PM)
A watch which gains uniformly, is 5 minutes slow at 8 o' clock in the morning on Sunday and it is 5 min. 48 sec fast at 8 p. M. On following Sunday. When was it correct?
Konxie said:
(Thu, Jun 7, 2012 02:29:39 AM)
Say its 12 o' clock:
The minute hand and the hour hand points towards 12
After an hour i.e at 1 o' clock:
The minute hand points at 12 and the hour hand points 1
The difference between the two hands after 60 min (1 hr) is 55 spaces but the hands did not coincide!
They will coincide when 60 spaces are covered
And to cover 60 spaces it takes = (60/55*60) = 65.4545 min (in a normal clock)
Now given in question is that the hands coincide at 64 min (defective clock)
So loss in time when the hands coincide is 65.4545 - 64 = 1.4545 min (this loss happens for every 64 min in our defective clock)
So for 1 min our loss is = 1.4545/64 min
For a day 1.4545/64*(24*60) = 32.7 min
@Naresh : just remember this
If coinciding time > 65(5/11) then our clock is going slow than normal (our watch is loosing time) and if coinciding time < 65(5/11) then its going fast than normal (or gaining time).
By 65(5/11) i mean 65.4545 and not (65*5)11
And we say loosing time in questions just to state the irregularity in time.
HOPE THIS CLEARS IT ALL
Dinesh said:
(Sun, Jul 29, 2012 11:04:27 PM)
Well said Konxie.
Priya said:
(Fri, Aug 31, 2012 08:02:16 PM)
I can't understand this problem 65*5/11-64
Sachin said:
(Tue, Jan 1, 2013 04:32:06 PM)
First consider in how many minutes, hands should coincide.
55 min. spaces are covered in 60 min.
60 min. spaces will be covered in, 65 (5/11) i.e. 65.45 minutes.
But this clock is taking 64 minutes to coincide hence it is 1.45 min slow to actual time (65.45-64=1.45).
In 64 min of journey clock is 1.45 min slow, then
in 24*60 min it will 32.62 min slow.
=(24*60*1.45*1)/64= 32.62 or 32(8/11).
Koti said:
(Sun, Feb 24, 2013 12:06:59 PM)
I am not able to understand how 55 min. Spaces are gained by minute hand in 60 min period. Can anybody explain?
Amit said:
(Thu, May 16, 2013 03:37:48 PM)
Just imagine hour hand and minute hand starting at 12 O'clock. After 1 hour, the minute hand will be at 12 whereas the hour hand will be at 1. So what is the difference between them? it's 55 "Minute Space".
So, it takes 1 hour to cover 55 minute spaces, for overlapping they should cover total 60 minute space.
min.