Odd days of a year X = Remainder of [No. of days in the year X / 7].
[Where 7 --> For every 7 days, the day will be repeated, thats why we are dividing the total number of days of an year by 7. If it has any remainder then it will be considered as an odd day for that year.]
The required remainders (odd days) for the different years are given below:
For 2006: 365/7 = 1 (Total no. of days in 2006 is 365)
For 2007: 365/7 = 1
For 2008: 366/7 = 2 (Leap year, hence Feb month has 29 days)
For 2009: 365/7 = 1
Therefore, total number of odd days = 5.
Given day is 'Sunday' and total no of odd days is '5'.
31 dec 2005 = Saturday
365/7 = 52+1/7
2006= 1 odd day
2007= 1 odd day
2008=> 366/7 = 52+ 2/7=> 2 odd day
then 31 Dec 2008= Thursday
and 1 Jan 2009 = Friday.
Nilesh said:
(Sat, Aug 28, 2010 04:36:09 AM)
How do we know leap year of that specific year?
Vijaya said:
(Tue, Sep 14, 2010 10:41:13 AM)
Given :.
Jan 1, 2006 is sunday.
Jan 1, 2010 =?.
Consider completed year before 2010 i.e 2009 (since 2010 was starting).
9/4=2 (2 leap years are there. Here it is divided by 4 because for every 4 years we get leap year).
Leap year=2*2=4.
Non leap =7*1=7.
Total = 11.
Jan 1st=1 day.
11+1=12.
12/7 = 5.
Friday.
Veer Singh Pal said:
(Thu, Sep 30, 2010 05:12:05 AM)
If any year divided by 4 with out reminder its year known as leep year.
E.g: 2008/4 = 502 (no reminder)
And in this year were 29 days in Feb.
Basavaraj said:
(Sat, Oct 23, 2010 01:39:24 PM)
I want clear method to calculate odd days.
Manu said:
(Fri, Nov 12, 2010 04:36:35 AM)
Everytime the odd days are considered from sunday onwards i.e.,if there are are 0 odd days then we take the day as sunday and the count follows likewise
Shaunak said:
(Sun, Nov 28, 2010 09:47:32 AM)
@veer singh pal:your answer is partially correct.for years like 1600,1700,1800,1900,2000 etc,we need to divide by 400.for other nos.,it needs to be a multiple of 4.
Ashish Gupta 07666076747 said:
(Mon, Dec 6, 2010 11:59:09 PM)
Thanx a lot.
Arun Anoop M said:
(Tue, Dec 7, 2010 01:35:37 AM)
Thanks vijaya
100=24 leap yr+[100-24]ordinary days
=[24*2]+76
=124
my way is
124=17weeks+5 ordinary days
So answer is 5.
But your way is very easy
124/7=5(remainder).
Priyavel said:
(Wed, Dec 15, 2010 07:13:11 AM)
Hai Nilesh.
We divide year by 400. If remainder comes 0 means that year is leap year.
Dhanagopal said:
(Thu, Dec 16, 2010 03:34:05 AM)
I want briefly to find odd days.
Boomathi said:
(Thu, Dec 23, 2010 10:23:54 AM)
Please tell how do we know the leap year?
Latha said:
(Wed, Dec 29, 2010 05:56:59 AM)
@Boomathi.
We know the given year is leap year or not, that year is divided by 4. That number (year) does not give any remainder that year is called leap year.
formula=day+mon no.+(x-1900)+(x-1900)/4
x= the year we have to calculate
Eg:
16-may-2011
for=16+2+(2011-1900)+(2011-1900)/4
=16+2+111+111/4
=16+2+111+27
(here we should not take the no behind decimal i.e 111/4=27.75)
=156
156/7=2(reminder)
mon =2
Seetharaman said:
(Mon, Jan 17, 2011 04:15:14 AM)
Thanks pavithra.
Suman said:
(Mon, Jan 31, 2011 08:17:06 AM)
Many many thanx...Pavithra
Kamal said:
(Fri, Feb 4, 2011 02:38:59 AM)
Vijay can we do the same calculations for years like 2000, 1990, 1980 ?
Kamal said:
(Fri, Feb 4, 2011 02:56:40 AM)
Pavithra can you apply you are concept for this date?.
1st Jan 2008.
If please explain it with steps.
Sonu Navgotri said:
(Thu, Feb 17, 2011 05:58:38 AM)
For non-leap year odd number = 1 .
For leap year odd number = 2.
Dg1234 said:
(Thu, Mar 3, 2011 03:15:47 PM)
This formula does not work on leap year. Pavithra..I am so sorry
Akhtar said:
(Tue, Mar 8, 2011 10:06:57 AM)
I think sundar gave perfect ans.
Priya said:
(Tue, Mar 22, 2011 04:16:59 AM)
Multiples of 4 and multiples of 400 are leap years but multiples of 100 not a leap year
Priyanka said:
(Thu, Mar 24, 2011 03:32:41 PM)
Guys give a simple and easy method to find the leap year like pavithra has given to find the week day of a certain date.
Siddharth said:
(Mon, Apr 4, 2011 02:21:42 PM)
Well done sundar.
Let me know that simple method to find leap year.
Rajellam said:
(Fri, Apr 29, 2011 05:50:09 AM)
Thank you sunder. Actually I don't know how to calculate. But now I can do with help of you. Thak you.
Deena said:
(Tue, May 17, 2011 11:37:36 AM)
Pavithra your formula is perfect and easy method. Thank you.
Some X said:
(Thu, May 19, 2011 09:02:58 AM)
Vijaya please don't confuse students with your typical explanation. Sunder's explanation is pretty simple when compared to yours. Don't make students to give up their effort in learning something by giving these type of difficult explanations.
Sidhu said:
(Tue, Jun 14, 2011 10:52:07 PM)
Pavithra. Thanks for your approach. Can u please say me why 1900 is used there (possibly some concept behind)?
Revathi said:
(Wed, Jun 29, 2011 11:54:54 AM)
Hi pavithra, tell me if they asked for the year with below 1900. Because the value will be gone to minus so what to do?
Vallinath said:
(Mon, Jul 25, 2011 11:35:50 PM)
Pavithra you said sat code 7 or 0 when we use 7 and when we use 0 please tell me.
Faiza said:
(Thu, Jul 28, 2011 10:25:29 AM)
1 ordinary year = 365days = 52weeks + 1day
so, each ordinary year has 1 odd day.
1 leap year = 366 days = 52 weeks + 2 days (since 52 weeks=364days so, in leap year , to get 366 days we add 2 in 364)
so, each leap year has 2 odd days
100 years = 76 ordinary years + 24 leap years
= 76 multiply with its odd day i.e 1 + 24 multiply with its odd days i.e 2
= 76 + 48
=124 odd days
This means that every 100 years contain 124 odd days.
Aparna said:
(Wed, Aug 3, 2011 10:36:15 PM)
Pavithra very wrong method. How can you calculate 16th july 1776 ?
January 0 (in leap year 6)
February 3 (in leap year 2)
March 3
April 6
May 1
June 4
July 6
August 2
September 5
October 0
November 3
December 5
Days Table:
1. Look up the 1900s in the centuries table: 0
2. Note the last two digits of the year: 82
3. Divide the 82 by 4: 82/4 = 20.5 and drop the fractionalpart: 20
4. Look up April in the months table: 6
5. Add all numbers from steps 1-4 to the day of the month (in this case, 24): 0+82+20+6+24=132.
6. Divide the sum from step 5 by 7 and find the remainder: 132/7=18 remainder 6
7. Find the remainder in the days table: 6=Saturday.
Sekhar said:
(Sat, Oct 22, 2011 10:40:58 PM)
Thanks pavithra
Girija said:
(Fri, Oct 28, 2011 11:19:22 AM)
Sridhar my quetion for you how you wrote century table we have to remember that or else is there any calculation but your expalanation so nice I have that doubt only, so please clarify that and before 1700 how you know value ?
Vijay said:
(Tue, Nov 1, 2011 06:10:33 PM)
365 day = 1 year, day364/7days = 54weeks, balance 1 day that will be conce considered as ODD days.
If it is leap year total no of days for = 366, 364/7 = 54 weeks balnce 2 days.
Satishmohan said:
(Mon, Nov 7, 2011 12:09:03 AM)
Sridhar my quetion for you how you wrote century table we have to remember that or else is there any calculation but your expalanation so nice I have that doubt only, so please clarify that and before 1700 how you know value ?
Abhinav said:
(Mon, Nov 7, 2011 01:35:57 PM)
It is Thursday on 25th of September. What day will it be on the 25th of October in the same year?
Subhashree said:
(Thu, Nov 10, 2011 08:59:33 AM)
@Sridhar, how we know the centuries table value or months table value?
Vipanchi said:
(Mon, Nov 21, 2011 10:48:51 AM)
Hi could you please explain clearly formula to find the day of the week.
Kundan K said:
(Sat, Nov 26, 2011 05:39:35 PM)
Hi friends,
There are 52 weeks in a year.And there are 7 days a week.So, the closest factor of 7 is 49.And 52-49=3.So after 49 days again there will be Sunday.So,add 3 days to Sunday that is Wednesday.Now similarly continuously add 3 days for 4 times as there is difference of 4 years between 2010 & 2006.
Therefore the ans is "FRIDAY".
Chandu said:
(Sat, Nov 26, 2011 10:24:55 PM)
Thanks sundar
Intaj said:
(Sat, Dec 3, 2011 07:12:59 PM)
Hi, you can do it easily follow my shortcut rule :-
jan = (1) = 3 jan = 31/7 = remain = 3
feb = (2)= 0 feb= 28/7 = remain = 0
march = (3)= 3
april = (4)= 2 april = 30/7 = reminder = 2
may = (5) = 3
june = (6) = 2
july = (7) =3 ====================================
aug = (8)= 3 (1 , 3, 5, 7, 8, 10, 12) = 3
sept = (9)= 2 ( 4, 6, 9, 11) = 2
oct = (10)= 3 2= 0 (Feb)
nov = (11) = 2
dec = (12) = 3 JUST REMEMBER ABOVE
Arkright said:
(Thu, Dec 15, 2011 10:21:43 PM)
Why do you divide with is it 4 or 7 to get a leap /ordinary year am confused some of you using 7 while others 4. Please explain?
Manish Tiwari said:
(Fri, Dec 16, 2011 09:16:17 PM)
Thanks pavitra. Really good dear.
Sreehitha said:
(Sat, Jan 7, 2012 02:59:16 PM)
Pavitra, can you please explain for 1st jan 2008 as it is a leap year how to approach it. The example 16 may 2011 which you have given is for non leap year right.
Nallathambim said:
(Thu, Jan 12, 2012 12:51:23 PM)
On 31st December 2009, it was Thursday.