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Aptitude - Calendar - Discussion

@ : Home > Aptitude > Calendar > General Questions - Discussion

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"Nothing in life is to be feared, it is only to be understood."
- Marie Curie
4. 

What will be the day of the week 15th August, 2010?

[A]. Sunday[B]. Monday
[C]. Tuesday[D]. Friday

Answer: Option E

Explanation:

15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)

Odd days in 1600 years = 0

Odd days in 400 years = 0

9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days 4 odd days.

Jan.  Feb.   March    April    May  June  July  Aug. 
(31 +  28  +  31   +   30   +  31  + 30  + 31  + 15) = 227 days

227 days = (32 weeks + 3 days) 3 odd days.

Total number of odd days = (0 + 0 + 4 + 3) = 7 0 odd days.

Given day is Sunday.


Sumit said: (Mon, Oct 18, 2010 03:50:32 AM)    
 
11 odd days= 4 odd days. Can't understand.

Hary said: (Sun, Dec 12, 2010 02:49:50 PM)    
 
Sumit,

11 days are left and in those 11 days,week days (7) are subtracted so the remaining are 11-7=4 odd days.

Saurav said: (Tue, Jan 25, 2011 11:20:37 AM)    
 
How 1600 and 400 gets 0 odd days ?

Boney said: (Wed, Feb 23, 2011 06:54:43 AM)    
 
If we divide 1600/400 we will get zero as remainder so it has zero odd days.
so in 2000 yrs we have 0 odd days.
In 9 yrs there r 2 leap years
leap yrs have 2 odd days(366/7 2 as remainder) and
non leapyr have 1 odd day totaling we have 2*2+7*1=11 odd days
Now cal no: of days in 2010 upto aug 15 then dividing by 7
will give no of odd days 2010 which is 3.

Rashi said: (Sat, Mar 12, 2011 06:34:02 AM)    
 
Thanks boney.

John said: (Wed, Mar 16, 2011 06:46:26 AM)    
 
Why we are taking the 2000 years as 1600 and 400 years ?

Sundar said: (Wed, Mar 16, 2011 06:50:52 AM)    
 
@John

You can find the answer for your question in this page.

http://www.indiabix.com/aptitude/calendar/discussion-638

Hope this help you. Have a nice day!

Rakesh said: (Wed, Jul 6, 2011 12:49:41 PM)    
 
How can I know 9years has (2leap + 7 nonleap)?

Rupali said: (Sat, Aug 27, 2011 12:39:57 PM)    
 
Please can you tell me how you write the.

Total number of odd days = (0 + 0 + 4 + 3) = 7 odd days.

I can't understand this step.

Trilochan said: (Tue, Sep 6, 2011 04:09:53 PM)    
 
@Rupali: First you go through the Important formluas which is given in the 1st page .

Vaibhav said: (Thu, Sep 15, 2011 12:04:23 PM)    
 
Hey, this type of questions can be easily done by following formula
---------------------------------------------------------------------------------
f= K+[(13m-1)/5]+ d+[d/4]+[c/4]-2c

Here k= date of which you have to calculate(15 in above que.)
m= month (for march, m=1 and so on..for jan m=11)
d= last two digit of given year(10 in above que.)
c= first two digit of given year(20 in above que.)
---------------------------------------------------------------------------------
note: take only integer value after division for ex. 13/5=2
---------------------------------------------------------------------------------

For given question

15th August, 2010?

f=15+[(13*6-1)/5]+10+[10/4]+[20/4]-2*20
=15+15+ 10 + 2 + 5 -40
=7

Now 7%7==0

So its SUNDAY.

Nithya said: (Tue, Sep 20, 2011 11:06:41 PM)    
 
How for march the value of month is 6? I don't understand the month value.

Vishnu said: (Tue, Sep 27, 2011 05:32:35 AM)    
 
9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days 4 odd days.

How com tat 4 odd days ?

Sudhakar said: (Tue, Oct 4, 2011 04:39:06 PM)    
 
@vishnu : those 4 days are the result of 11days(divide these 11days into weeks and days, so u get 7+4,here 7days makes a week and do count those 4 extra days.) so finally we get 4ODD DAYS..

Malathy said: (Sat, Oct 22, 2011 11:50:13 AM)    
 
Dear friends,

Pls. explain which day will come on 25th dec 1992 with step by step procedure

Nagaraju said: (Sat, Nov 12, 2011 06:04:41 PM)    
 
Friends can you explain 7%7=0 taken as sunday how?

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