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Aptitude - Alligation or Mixture - Discussion

@ : Home > Aptitude > Alligation or Mixture > General Questions - Discussion

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"To err is human; to forgive, divine."
- Alexander Pope
3. 

A can contains a mixture of two liquids A and B is the ratio 7 : 5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7 : 9. How many litres of liquid A was contained by the can initially?

[A]. 10[B]. 20
[C]. 21[D]. 25

Answer: Option E

Explanation:

Suppose the can initially contains 7x and 5x of mixtures A and B respectively.

Quantity of A in mixture left = 7x - 7 x 9 litres = 7x - 21  litres.
12 4

Quantity of B in mixture left = 5x - 5 x 9 litres = 5x - 15  litres.
12 4

7x - 21
4
= 7
5x - 15  + 9
4
9

28x - 21 = 7
20x + 21 9

252x - 189 = 140x + 147

112x = 336

x = 3.

So, the can contained 21 litres of A.


Teja said: (Sat, Jan 8, 2011 11:46:54 AM)    
 
Can You explain in other way ?

Amara said: (Wed, May 25, 2011 07:40:08 PM)    
 
How to calculate mixture left?

Debjyoti said: (Sat, May 28, 2011 03:40:42 PM)    
 
Total mixer is x.
A=7x/12 B=5x/12
after drawn 9 lit of mixer........
mixer remain(x-9)

So the new ratio of A:B is ...
A=7(x-9)/12 and B=5(x-9)/12
now drawn 9 lit filled with B
so B now contain B=5(x-9)+9/12...........
now the new ratio of mixer is A:B=7:9
we know the new value of A and B...........put that in this equation

7(x-9)/12:(5(x-9)+9)=7:9-------if u calculate further u ll get the X value as 36

Put that x value in A=7x/12, so here you can get answer of A contain initially.

Sree said: (Sun, Jun 12, 2011 02:38:06 PM)    
 
Hi Debjyoti,

Can you give the explination how you got x=36 using below equation?

7(x-9)/12:(5(x-9)+9) = 7:9

Karthikeyini said: (Sun, Jun 26, 2011 05:52:56 AM)    
 
(7x-(21/4))/((5x-(15/4))+9)

In this term how 9 occured at the end ? Can anyone explain this ?

Prithvi Chauhan said: (Sun, Jun 26, 2011 08:24:32 AM)    
 
Please can you explain in any other simple way?

Gowtham said: (Sat, Sep 3, 2011 04:36:50 PM)    
 
Hi guys,

Find the pure liqued of A in initial

Assume pure liqued x,
Quantity of a measured left formula=(pure A liquid - mix liquid)
Pure liquid of A=7x
Mix liquid of A=(7/12)*9
here 9 is also mixture

So, quantity of a measured left A=(7x-(7/12)*9)=7x-21/4
the same rule
quantity of a measured left B=(5x-(5/12)*9)=5x-15/4
(7x-(21/4)/5x-(15/4)+9)=7/9

Given here that 9 is add with b
ans x=3
ratio of 7

So=7*3=21 that all

San said: (Mon, Sep 19, 2011 06:04:10 AM)    
 
Is there any easy way to do it ?

Preethi said: (Wed, Sep 21, 2011 07:03:42 PM)    
 
Any simple method please.

Silu said: (Sat, Oct 15, 2011 07:45:41 PM)    
 
Total mixer is x.
A=7x/12 B=5x/12
after drawn 9 lit of mixer........
mixer remain(x-9)

So the new ratio of A:B is ...
A=7(x-9)/12 and B=5(x-9)/12
now drawn 9 lit filled with B
so B now contain B=5(x-9)/12 +9...........
now the new ratio of mixer is A:B=7:9
we know the new value of A and B...........put that in this equation

7(x-9)/12:(5(x-9)/12+9)=7:9
=>9x-81=5x-45+108
=>x=36

as knon A=7x/12

=>A=7*36/12
=21
(enjoy...)

Varsha said: (Wed, Jan 18, 2012 05:45:12 PM)    
 
Thanks silu.

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