Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg will be:
[A].
Rs. 169.50
[B].
Rs. 170
[C].
Rs. 175.50
[D].
Rs. 180
Answer: Option B
Explanation:
Since first and second varieties are mixed in equal proportions.
So, their average price = Rs.
126 + 135
= Rs. 130.50
2
So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find x.
By the rule of alligation, we have:
Cost of 1 kg of 1st kindCost of 1 kg tea of 2nd kind
Totally there are 4kg mixture which costs 153.
therfore,(126+135+x)/4=153
x=351.
Here x is the price for 2Kg.
therefore x=175.50
Ragul said:
(Tue, Oct 12, 2010 07:22:11 AM)
Problem is simple.
(126+135+x) * (k+k+2K) =153* (k+K+2K).
When you solve above one, you will get x.
Uma Upadhyay said:
(Fri, Oct 15, 2010 02:50:39 AM)
Say the unknown quantity is X.
Then (126*1+135*1+2*x)/(1+1+2)= 153
on solving X= 175.50
Satish said:
(Mon, Nov 22, 2010 09:08:10 AM)
x - 153 = 1
------
22.50
will u explaim dis step,,,,,,,Plz,,,,
Ramakhanna said:
(Sun, May 15, 2011 02:39:35 AM)
Let the three varieties be A,B,C.
the ratio is given as 1:1:2.
Let x be the price of third variety per kg.
A B C
the cost is: Rs.126/kg Rs.135/kg Rs.x/kg
the amount
(from ratio): (1/4)kg (1/4)kg (1/2)kg
(in kg.)
cost of three varieties per kg = cost of the mixture per kg
so,
(126*(1/4))+(135*(1/4))+(x*(1/2))=153
after making calculation, x=175.5
so, the price of third variety per kg will be Rs.175.5
x - 153 = 22.50