A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?
[A].
4 litres, 8 litres
[B].
6 litres, 6 litres
[C].
5 litres, 7 litres
[D].
7 litres, 5 litres
Answer: Option A
Explanation:
Let the cost of 1 litre milk be Re. 1
Milk in 1 litre mix. in 1st can =
3
litre, C.P. of 1 litre mix. in 1st can Re.
3
4
4
Milk in 1 litre mix. in 2nd can =
1
litre, C.P. of 1 litre mix. in 2nd can Re.
1
2
2
Milk in 1 litre of final mix. =
5
litre, Mean price = Re.
5
8
8
By the rule of alligation, we have:
C.P. of 1 litre mixture in 1st can C.P. of 1 litre mixture in 2nd can
If it is 6litres of milk and 6litres of water making 12litres of the mix,then does not it mean that milk and water is 50% and 50%??how will it be in the ratio 3:5 to satisfy the requirement??Please explain this..
Mahendra said:
(Sat, Nov 13, 2010 03:25:25 PM)
@moncy The solution to this problem is right
Ans is [B] 6 litres, 6 litre
6 liters from first can gives 1.5 litre of water and 4.5 of milk
6 liters from second can gives 3 litres of water and 3 litres of milk
so, (1.5+3)/(4.5+3)= 4.5/7.5 = 0.6 = 3/5
Manish said:
(Fri, Dec 17, 2010 11:49:25 AM)
Initially water and milk percent was 25% water and 75%milk
in 2nd container 50-50%
finally milk was 12 litre
ratio was 3:5 means 3x water and 5x milk s0 5x=12 ;x= 12/5
water 36/5
milk percentage 12/(12+36/5)=62.5
soincrease in milk percentage 12.5%each so omly one option is matching
Nagendramurthy said:
(Thu, Jun 23, 2011 06:08:59 AM)
Friends see can also solve the problem..
initially water and milk in first can are in 1/4 and 3/4
in the second can 1/2 and 1/2
therefore total (1/4)+(1/2) of water and (3/4)+(1/2)
i.e (3/4) of water and (5/4) of milk
If we compare it already in the ratio of 3:5
So we have add equal amount of water and milk in order to maintain the ratio same..
Charan said:
(Fri, Nov 4, 2011 06:34:41 PM)
Lets take total in terms of mixture in x & y
new water mixture = x/4+x/2
milk = 3y/4 + y/2
ratio comes out as x:y = 3:5
thats its self gives the new mixture
2x=12 or 2y=12
6ltr n 6ltr
Ratio of two mixtures =
